Question

If k + 1 = sec2 0(1 + sin 0)(1 - sin o), then
find the value of k.
​

Answer 1

$\mathfrak{\huge{Answer:-}}\\\bold{k + 1 = {sec}^{2}θ (1 + sinθ)(1 - sinθ)} \\ k + 1 = {sec}^{2} θ[ {(1)}^{2} - {(sinθ)}^{2} ] \\ k + 1 = \frac{1}{ {cos}^{2}θ } \times 1 - {sin}^{2} θ \\ k + 1 = \frac{1}{ {cos}^{2}θ } \times {cos}^{2} θ \\ k + 1 = 1 \\ k = 1 - 1 \\ \bold{\large{ \boxed{\boxed{k = 0}}}}$