Question

If k + 1 = sec² θ(1 + sin θ) (1 – sin θ), then the value of k is

1 point

0

1

-1

2

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Answer 1

Answer:

k = 0 will be the right answer.

Answer 2

${\underline{ \mathtt{\red{k} \green{u}\mathtt\blue{s} \purple{h} \mathtt \orange{i}\pink{i}}}}\:$

Let theta be @ K+ 1 = sec square@ [ 1- sin@]{1 - sin@} K+ 1 = sec square@ [1] - {sin square@} K+1 = sec square @[ cos square @] K +1= 1 K=0 Hope this will help you