Question

If (k- 1)x²+kx+1 has a zeroes find
the other zeroes.​

Answer 1

Answer:

You have a typo becuase you forgot to specify the first zero; however one zero is f(-1); as such, (k-1)x^2 -x^2 + kx + 1= 0 —-> distribute the first “k” and then rearrange terms to get k(x^2) +kx -x^2 + 1; which can be rewritten in the form k(x^2 + x) - x^2 +1 = 0; now if we take the k to be constant and negligible then we have then we have the solution x + 1= 0 because we can cancel the x^2’s to get the solution x = -1; now check this conditon in the original (k-1)x^2 + kx +1 = 0; (k-1)(-1)^2 + k(-1) +1 = 0—->k -1 -k +1 =0 and this is a true statement . The other obvious zero is f(1)…:/

HOPE IT HELPS ❤️