Math, asked by queensp73, 8 months ago

If k+2, 2k+1 , 15 are three consecutive terms of an arithmetic sequence, then, find a) find the value of k. b) write the sequence. No spam plz

Answers

Answered by pinumallasaketh21
4

Answer:

மரியாதைக்குரிய மேடம்

Step-by-step explanation:

a) The value of K is 5

solution

(2k + 1) - (k + 2) = 15 - (2k + 1)

a2-a1=a3-a2

K-1=14-2k

3K=15

K=5

b) sequence=7,11,15,19,23.......

just before you answered my question I have some doubts in it can you please message me for discussion because my idea is some what different from you because India exports food grains only to maintain good relationships with other countries

message me once for answer discussion

நன்றி

Answered by TamizhanSiddarth
3

Answer:

a) k = 5

b) 7, 11, 15

Step-by-step explanation:

If k+2, 2k+1, 15 are three consecutive terms of an A.P,

2b = a + c

2(2k+1) = k + 2 + 15

4k + 2 = k + 17

3k = 15

k = 5

I am Siddarth and I'm Tamizhan. Please Inbox me

Similar questions