Question

If k+2, 4k-6, 3k-2 are consecutive term of an AP then k=?

Answer 1

Answer:

$k = 3$

Step-by-step explanation:

We know that in AP,common difference d,is equal.

If k+2, 4k-6, 3k-2 are consecutive term of an AP then to find k

find the difference of two consecutive terms and put them equal

$T_2 - T_1 = T_3 - T_2 \\ \\ 4k - 6 - k - 2 = 3k - 2 - 4k + 6 \\ \\ 3k - 8 = - k + 4 \\ \\ 3k + k = 4 + 8 \\ \\ 4k = 12 \\ \\ k = \frac{12}{4} \\ \\ k = 3$

Hope it helps you.

Answer 2

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