if k+2,4k-6,3k-2 are consecutive terms of an AP then k=__
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k=k+2,4k-6,3k-2 are consecutive terms of an AP then k=__
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7
Answer:
4k-6-k+2=3k-2 -4k-6
3k-4=-k-8
3k+k=-8+4
4k=-4
k=-4/4
k=-1
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