Question

If k+2, 4k-6 , 3k-2 are the three consecutive terms of an A.P , then the value of k is ?

Answer 1

Answer:

Step-by-step explanation:

If these form an AP

then,k -  

4k-6 - k-2 = 3k-2 - 4k+6

3k - 8 = -k + 4

3k + k = 4 + 8

4k = 12

k = 3

Answer 2

Answer:3

Step-by-step explanation:

In AP difference of consecutive terms is equal in each case:

HENCE ,   (4k-6) - (k+2) = (3k-2) - ( 4k-6 )

                    4k -6 -k -2 = 3k- 2 -4k+6

                            3k - 8 = -k+4

                            3k +k = 4+8

                                 4k = 12

                                    k=3