Question

If k+2 , 4k-6 and3 k-2 are three consecutive terms of an AP, then the value of k is a)3 b)-3 c)4 d)-4

Answer 1

Answer:

Step-by-step explanation:

To be terms of an AP the common difference between two consecutive terms must be the same

So if k+2, 4k-6 & 3k-2 are consecutive terms of an AP, then

4k-6 – (k+2) = 3k-2 – (4k-6)

4k - 6 - k - 2 = 3k - 2 - 4k + 6

3k - 8= –k + 4

4k = 12

k =12/4

  = 3.