Math, asked by laxmisharma24481, 4 months ago

If k=2,Find the value of p(k)= 1-k²+2k³​

Answers

Answered by suraj5070
234

 \sf \bf \huge {\boxed {\mathbb {QUESTION}}}

\sf \bf If \:k=2,\:Find \:the \:value\: of\: p(k)= 1-{k}^{2}+2{k}^{3}

 \sf \bf \huge {\boxed {\mathbb {ANSWER}}}

 \sf \bf \huge\underline {k=2}

 \sf \bf \implies {p(k)= 1-{k}^{2}+2{k}^{3}}

 \sf \bf \implies {p(2)= 1-{(2)}^{2}+2{(2)}^{3}}

 \sf \bf \implies {p(2)=1-4+2(8)}

 \sf \bf \implies {p(2)=-3+16}

 \implies{\boxed{\color {green} {\sf \bf p(2)=13}}}

 \sf \bf \huge {\boxed {\mathbb {HOPE \:IT \:HELPS \:YOU}}}

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 \sf \bf \huge {\boxed {\mathbb {EXTRA\:INFORMATION}}}

 \tt {\underbrace {\overbrace {Identities}}}

 \sf \bf {(a+b)}^{2}={a}^{2}+2ab+{b}^{2}

 \sf \bf {(a-b)}^{2}={a}^{2}-2ab+{b}^{2}

 \sf \bf (a+b) (a-b) ={a}^{2}-{b}^{2}

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