Question

If (K-2) is the H.C.F of 3,9,and 12 find the value of p in 2k-p=4​

Answer 1

Step-by-step explanation:

from the question the value of p is 72 and the value of ki 38

Answer 2

Answer:

p = 6

Step-by-step explanation:

Now,

3 = 1 × 3 = 3¹

9 = 3 × 3 = 3²

12 = 2 × 2 × 3 = 2² × 3

HCF is the common number with the lowest power

∴ HCF = 3

But we are given, HCF (3, 9, 12) = k - 2

Thus,

3 = k - 2

k = 3 + 2

k = 5 ---- 1

Now,

2k - p = 4

From eq.1 we get,

2(5) - p = 4

10 - p = 4

p = 10 - 4

∴ p = 6

Hope it helped and believing you understood it........All the best