Question

if (k-2,k+1)is a solution of the equation 2x+3y=4, then find the value of k. ​

Answer 1

Answer:

$\Huge {\fbox {\red {\fbox {\blue {\color{blue}{ANSWER}}}}}}$

$\large \mathrm \color{black}{k = 1}$

Step-by-step explanation:

$\small \mathrm \color{black}{Let\:k - 2 \: be \: x \: and \:k + 1 \: be \: y }$

$\small \mathrm \color{black}{As \: 2x + 3y = 4}$

$\small \mathrm \color{black}{put \: x = k - 2 \: and \: y = k + 1}$

$\small \mathrm \color{black}{2(k - 2) + 3(k + 1) = 4}$

$\small \rm \color{black}{2k - 4 + 3k + 3 = 4}$

$\small \rm \color{black}{5k - 1 = 4}$

$\small \rm \color{black}{5k = 4 + 1}$

$\small \rm \color{black}{5k = 5}$

$\small \rm \color{black}{k = \frac{5}{5} }$

$\small \rm \color{black}{k = 1}$

Answer 2

Answer :

k =1

Step-by-step explanation:

Let k -2 be x and k + 1 be y

As 2x + 3y = 4

put x = k - 2 and y = k + 1

2(k - 2) + 3(k + 1) = 4

2k - 4 + 3k + 3 = 4

5k - 1 = 4

5k = 4 + 1

5k = 5

k = 5/5

k = 1

hope it will help you...