If k+2,k,3k-2 are the consecutive terms of ap then k=?
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To be terms of an ap the difference between the two consecutive numbers must be the same.
So, if k+2, k, 3k-2 are in AP then
=>k-(k+2)=3k-2-k
=> -2=2k-2
=> 0=2k
=> k=0
Therefore the terms are 2, 0, - 2.
Hope it helps you
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