Question

If k+2, k, 3k+2 are three consecutive terms of A.P. then k= ​

Answer 1

Step-by-step explanation:

it's observed that the common difference is +2

so ,

k+2+2= k

k+4 = k

but seeing this the a.p. isn't followed

probably the quesiton is of k+2,k, 3k-2

Given : k+2,k,3k−2 are in A.P.

∴k−(k+2)=(3k−2)−k

∴k−k−2=3k−2−k

∴−2=2k−2

∴2k=0

∴k=0

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