Question

if k,2k-1,2k+1 are three consecutive terms of an AP,find k?​

Answer 1

Answer:

Given, k,2k-1,2k+1 are three consecutive terms of an AP

We know, if a,b,c are in AP then, 2b = a+c

=> 2(2k-1) = k+ ( 2k+1)

=> 4k - 2 = 3k + 1

=> k = 3

Answer 2

Answer:

Step-by-step explanation:

Given,

k,2k - 1,2k + 1 are three consecutive numbers of an A.P.

Let a1= k, a2 = 2k - 1, a3 = 2k + 1

We know that a,b,c are in A.P.

b - a = c - b

2k - 1 - k = 2k + 1 - (2k - 1)

2k - k -1 = 2k + 1 - 2k + 1

k - 1 = 2

k = 2 + 1

k = 3