Question

if k, 2k-1, 2k+1are in A.P, the value of k is​

Answer 1

Answer:

3

Step-by-step explanation:

Given,

k , 2k - 1 , 2k + 1 are in A.P

To find :-

What is the value of 'k'.

How To Do :-

As they said that k , 2k - 1 , 2k + 1 are in A.P. We know that if a , b , c are in A.P . Then common difference(d) will be same. Then, b - a = c - b. So by using this formula we need to equate those terms and we need to obtain the value of 'k'.

Formula Required :-

If a , b , c are in A.P :-

b - a = c - b

b + b = c + a

2b = a + c

Solution :-

k , 2k - 1 , 2k + 1 are in A.P

→ 2(2k - 1) = k + 2k + 1

2(2k) + 2(-1) = 3k + 1

4k - 2 = 3k + 1

Putting all variable terms to L.H.S and all constant terms o R.H.S :-

4k - 3k = 1 + 2

k = 3

∴ Value of 'k' = 3.