Math, asked by govindbiradar652, 10 months ago

If k,2k-1,2k+1are three consecutive terms of an A.P,the value of ‘k

(a) -2 (b) -3 (c) 3 (d) 6

Answers

Answered by biligiri
5

Answer:

answer

if a, b ,c ...are in A.P then b-a = c-b

in the given example

a = k , b = 2k-1 and c = 2k + 1

therefore 2k - 1 - k = 2k + 1 -(2k - 1)

=> 2k - 1 - k = 2k + 1 - 2k +1

=> k - 1 = 2

=> k = 3 Answer is option c

Answered by radha2216
0

Answer:

c)3

Step-by-step explanation:

k,2k-1,2k+1

3, 2(3)-1, 2(3)+1

3, 6-1, 6+1

3,5,7

Similar questions