Math, asked by aquafreshall, 11 months ago

If k,2k-1,&2k+1 are 3 consicutive terms of an AP. Find the value of k?​ hurry today I have exam please

Answers

Answered by Anonymous
1

Step-by-step explanation:

Since ,

k , 2k-1, and 2k+1 are the consecutive terms of an AP

→ 2k -1 -k =2k+1-(2k-1) = common difference

→ k-1=2

→ k =2+1=3

Hence , k =3

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Answered by Anonymous
1

Step-by-step explanation:

We have been given that

k , 2k-1, and 2k+1 are the consecutive terms of an Arithmetic Progression

We know that ,

T 2 - T1 = T3 - T1

→ 2k -1 -k =2k+1-(2k-1) = common difference

→ k-1=2

→ k =2+1=3

Hence , k =3

other method

If a , b , c are three consecutive terms of an AP then 2b = a + c .Use this formula to get the answer directly

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