Question

If K,2K-1 and 2K+1 are three consecutive terms of an A.P then value of K is

Answer 1

k,2k-1,2k+1 are in AP
2(2k-1)=k+2k+1
4k-2=3k+1
4k-3k=1+2
k=3
therefor the value of k is 3

Answer 2

Answer:

Step-by-step explanation:

to find the value of k,

a2-a1=a3-a2

2k-1-k=2k+1-[2k-1]

k-1=1+1

k=2+1

k=3

HOPE IT HELPS YOU