Question

If k, 2k-1 and 2k+1 are three consecutive terms of an A.P., the value of k is

Answer 1

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Given that,

If k, 2k-1 and 2k+1 are three consecutive terms of an A.P, find the value of k.

Let,

• a1 = k
• a2 = 2k - 1
• a3 = 2k + 1

We know that, the common difference (d) of AP terms are constant. So,

☯ a2 - a1 = a3 - a2

➡ (2k - 1) - (k) = (2k + 1) - (2k - 1)

➡ 2k - 1 - k = 2k + 1 - 2k + 1

➡ k - 1 = 2

➡ k = 2 + 1

➡ k = 3

$\boxed{∴ k = 3}$

Step-by-step explanation:

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