If k, 2k – 1 and 2k + 1 are three consecutive terms of an A.P., the value of k is
Answers
Answered by
10
2K-1-K=2K+1-(2K-1)
K-1=2K+2K+1
K-1=2
K=3
K-1=2K+2K+1
K-1=2
K=3
Similar questions