Question

If k, 2k –1 and 2k + 1 are three consecutive terms of an AP, the value of k is
A. – 2
B. 3
C. – 3
D. 6

Answer 1

B. 3

Step-by-step explanation:

k, 2k –1 and 2k + 1 are in an AP.

Then they are separated by a common difference d.

So we get 2k+1 -(2k-1) = d

   2k +1 -2k +1 = d

   2 = d

Also 2k-1 -k = d

    k-1 = d

   k = d + 1

   k = 2 + 1

  k = 3

Option B is the answer.