Math, asked by chalana15, 7 months ago

if k,2k-1 and 2k+1 are three consecutive terms of an AP the value of k is

Answers

Answered by Alok17118
0

Answer:

k=1

Step-by-step explanation:

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Answered by arpitrohila511
1

Answer:

k k,2k−1,2k+1 are three terms in A.P. Then,

Common difference between first two terms = 2k−1−k =k−1

Common difference between next two terms = 2k+1−2k+1 =2

The common difference between consecutive terms should be equal. 

Hence, k−1=2

k=3

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