if k,2k-1 and 2k+1 are three consecutive terms of an AP the value of k is
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0
Answer:
k=1
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Answered by
1
Answer:
k k,2k−1,2k+1 are three terms in A.P. Then,
Common difference between first two terms = 2k−1−k =k−1
Common difference between next two terms = 2k+1−2k+1 =2
The common difference between consecutive terms should be equal.
Hence, k−1=2
k=3
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