If k, 2k –1 and 2k+1 are three consecutive terms of an AP, the value of k is
a) 2
b) 3
c) – 3
d) 5
please answer fast
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Answer:
b)3
Step-by-step explanation:
ANSWER
k,2k−1,2k+1 are three terms in A.P. Then,
Common difference between first two terms = 2k−1−k =k−1
Common difference between next two terms = 2k+1−2k+1 =2
The common difference between consecutive terms should be equal.
Hence, k−1=2
k=3
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