Math, asked by sudesh1306, 6 months ago

If k, 2k –1 and 2k+1 are three consecutive terms of an AP, the value of k is

a) 2
b) 3
c) – 3
d) 5
please answer fast​

Answers

Answered by Anonymous
1

Answer:

b)3

Step-by-step explanation:

ANSWER

k,2k−1,2k+1 are three terms in A.P. Then,

Common difference between first two terms = 2k−1−k =k−1

Common difference between next two terms = 2k+1−2k+1 =2

The common difference between consecutive terms should be equal.

Hence, k−1=2

k=3

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