Math, asked by shrutiyadav13579, 7 months ago

If k , 2k-2,2k+1 are three consecutive terms of an A.P then the value of k is. *


Answers

Answered by DushyantkaushikKS
1

Answer:

k = 3

Step-by-step explanation:

An arithmetic progression (A. P.) is a sequence of numbers such that the difference between its consecutive terms is always constant and this constant difference between its consecutive terms is known as common difference of the A. P.

It means a2-a1 = a3-a2

a1=k, a2=2k-1, a3=2k+1

So, (2k - 1) - k = (2k+1) - (2k-1)

k - 1 = 2

k = 2 + 1

k = 3

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