If k 2k 3k are three terms of an ap find the value of k
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k 2k 3k are three terms of an ap for any value of k
Step-by-step explanation:
k , 2k , 3k are three terms of an AP
=> 2k - k = 3k - 2k
=> k = k
Hence k , 2k , 3k will be in AP independent of value of k
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Answer:
Step-by-step explanation:
k 2k 3k are three terms of an ap for any value of k
Step-by-step explanation:
k , 2k , 3k are three terms of an AP
=> 2k - k = 3k - 2k
=> k = k
Hence k , 2k , 3k will be in AP independent of value of k
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