Question

if k^3 = 1×2×4+2×4×8+3×6×12+.... +100×200×400/1×3×9+2×6×18+3×9×27+...100×300×900 and (x-3k) is a factor of the polynomial p(x) =x^2+ax-4 then the value of a is

Answer 1

=> k^3 =   1*2*4( 2^3 + 3^3 + 4^3 +.....+100^3) /  1*3*9( 2^3 3^3 + 4^3 +.....+100^3)

=>  k^3 = 8/27 
=>  k = 2/3 

so a/q:-    (x- 3*2/3) = (x-2) is a factor

so p(x) => 2^2 + 2a - 4 = 2a 
 given its a factor so remainder mus tbe equal to 0          
  => 2a=0 
  => a = 0/2 = 0.

Answer 2

Answer:

a=0

Step-by-step explanation:

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