Question

If (K-3) , (2K+1) and (4K+3) are 3 consecutive terms of an Arithmetic Progressions. Find the value of K
​

Answer 1

Answer:

k=2 is the answer

Step-by-step explanation:

in A.P 2b=a+c

2*2k+1=4k+3+k-3

4k+2=5k

k=2

Answer 2

$\huge\bold\color{magenta}{answer}$

$= > (2k + 1) - (k - 3) = (4k + 3) - (2k + 1)$

$= > 2k + 1 - k + 3 = 4k + 3 - 2k - 1$

$= > k + 4 = 2k + 2$

$= > k = 2$

HOPE ITS HELPFUL......:-)