Question

If (k –3), (2k + 1) and (4k + 3) are three consecutive terms of an A.P., find the value of k.

Answer 1

Answer:

k=2

Step-by-step explanation:

(2k+1)-(k-3)=(4k+3)-(2k+1)

2k+1-k+3=4k+3-2k-1

2k+2k-k-4k=3-1-3-1

3k-4k=-2

-k=-2

k=2