Question

If (k –3), (2k + 1) and (4k + 3) are three consecutive terms of an A.P., find the value
of k.

Answer 1

Answer:

Since these terms are consecutive terms of an A.P., the middle term must be the average of the other two.

⇒(k−3)+(4k+3)=2(2k+1)

⇒5k=4k+2

⇒k=2

Thus, the required value of k is 2.