Math, asked by prakharshweta109251, 11 months ago

if (k-3), (2k+1) and (4k+3) are three consecutive terms of an AP find the value of k ​

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Answered by Anonymous
5

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Answered by Anonymous
10

Solution

2k +1 -(k-3)

= 4k+3 - (2k+1)2 k +1 -k +3 = 4k +3 -2k -1k + 4

= 2k +2k

= 2

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