If (k-3),(2k+1) and (4k+3) are three consecutive terms of an ap.find the value of k
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Here they are in A.P. So-
2k+1-(k-3)=(4k+3)-(2k+1)
2k+1 -k +3 = 4k+3-2k -1
k+4=2k+2
k=2
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