Question

if k+3,k+2,3k-7 and 2k-3 are in proportion,find k​

Answer 1

Step-by-step explanation:

(k+3)/(k+2) = (3k-7)/(2k-3)

=> (k+3)(2k-3) = (3k-7)(k+2)

=> 2k^2 -3k + 6k - 9 = 3k^2 + 6k -7k -14

=> k^2 -4k - 5 = 0

Solve this,

k^2 -5k +k - 5 = 0

=> k(k -5) + 1(k-5) = 0

=> (k-5) (k+1) = 0

k = 5 or -1

ANS.

Here's your answer.Best of Luck