Question

if k+6, 3k, 4k+2 are in AP, find the value of k​

Answer 1

To Find :

• we need to find the Value of k.

Given :

• k + 6 , 3k , 4k + 2 are in AP

As we know that ,

➔ a2 - a1 = a3 - a2 common difference of AP is Always same ,

So,

• a1 = k + 6
• a2 = 3k
• a3 = 4k + 2

• By using the above concept finding value of k.

➔ 3k - (k + 6) = (4k + 2) - 3k

➔ 3k - k - 6 = 4k + 2 - 3k

➔ 2k - 6 = k + 2

➔ 2k - k = 2 + 6

➔ k = 8

Hence,

• Value of k is 6.

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