Question

If (k, 6) lies on graph of equation kx-ky+5=0, find value of k. ​

Answer 1

kx-ky+5=0

k(k)-k(6)+5=0

k2-6k+5=0

k2-5k-k+5=0

(k-1)(k-5)=0

if k-1 =0

k=1

if k-5=0

k=5

k=1,5