if k+9,4 are in G.P then k =
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Asked on November 22, 2019 by
Oorja Sunil
Find k such that (k+9), (k−6) and 4 form three consecutive terms of a G.P.
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ANSWER
It is given that k+9, k-6,4 are in G.P.
∴(k−6) is the geometric mean of (k+9) and (k+4)
(k−6)
2
=(k+9)×4
⇒k
2
−12k+36=4k+36
⇒k
2
−16k=0
⇒k(k−16)=0.
k is either 0 or 16
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