Question

if k+9,k-6,4are in gp then find the value of k​

Answer 1

Answer:

Step-by-step explanation:

K =25

Answer 2

YOUR ANSWER IS 25.

EXPLANATION:-

Given-

k+9, k-6, 4 are in AP.

To find-

The value of K.

Since the given terms are in AP so there common difference (d) must be equal.

Also we know that common difference = second term - first term

So d = (k-6) - (k+9) -----eq(1)

also,

d = (4) - (k-6) --------eq(2)

From eq(1) and eq(2) we get,

(k-6) - (k+9) = (4) - (k-6)

---> k-6-k-9 = 4-k+6 {by opening brackets}

---> -15 = -k+10

---> k = 10+15

---> k = 25

Therefore the required value of k is 25.

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