Question

If K earns 12% less than L, then how much percent more does L earn than K ?

Answer 1

Q:

If K earns 12% less than L, then how much percent more does L earn than K ?

Answer: 13.63% 

Explanation:

Required % is given by 
 
=> 12/100-12x100
 
= 1200/88
 
= 13.636%

Answer 2

In questions like this, your brain will almost immediately tell you that the answer is 20%. Beware, this tricks me a lot!

The actual solution is trivial.

A = 20% more than B

100 % of A = 20% of B + 100% of B

100 % of A = 120% of B

(100/120)% of A = 1% of B

(100*100/120)% of A =100 % of B

~83.33% of A = 100 % of B

So, B is ~(100 - 83.33 = ) 16.67% less than A.

Of course, I'm assuming here that when you said "A is 20% more than B," you meant A is 20% more that B with respect to B, and so on.

Please correct me if I'm wrong. This kind of logic always gets me.

Also, sorry I don't know to typeset that. :)