If K earns 12% less than L, then how much percent more does L earn than K ?
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Answered by
0
Q:
If K earns 12% less than L, then how much percent more does L earn than K ?
Answer: 13.63%
Explanation:
Required % is given by
=> 12/100-12x100
= 1200/88
= 13.636%
Answered by
5
In questions like this, your brain will almost immediately tell you that the answer is 20%. Beware, this tricks me a lot!
The actual solution is trivial.
A = 20% more than B
100 % of A = 20% of B + 100% of B
100 % of A = 120% of B
(100/120)% of A = 1% of B
(100*100/120)% of A =100 % of B
~83.33% of A = 100 % of B
So, B is ~(100 - 83.33 = ) 16.67% less than A.
Of course, I'm assuming here that when you said "A is 20% more than B," you meant A is 20% more that B with respect to B, and so on.
Please correct me if I'm wrong. This kind of logic always gets me.
Also, sorry I don't know to typeset that. :)
The actual solution is trivial.
A = 20% more than B
100 % of A = 20% of B + 100% of B
100 % of A = 120% of B
(100/120)% of A = 1% of B
(100*100/120)% of A =100 % of B
~83.33% of A = 100 % of B
So, B is ~(100 - 83.33 = ) 16.67% less than A.
Of course, I'm assuming here that when you said "A is 20% more than B," you meant A is 20% more that B with respect to B, and so on.
Please correct me if I'm wrong. This kind of logic always gets me.
Also, sorry I don't know to typeset that. :)
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