Question

If k is a constant value, then the
expected value of k is E(k)=
(1 Point

1.k
2.5
3.0
4.V(K)​

Answer 1

Answer:

0 is the correct answer

Step-by-step explanation:

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Answer 2

If k is a constant value, then the expected value of k is E(k)= k

Step-by-step explanation:

• We know that E(x) is equal to,

        $x_{1}P_{1} + x_{2}P_{2}+...+x_{n}P_{n}$

        = ∑$xP$

• Here, according to the given information, k is a constant and we need to find the value of k.
• Therefore E(k), by definition, is equal to E(k)= $kP_{1} +kP_{2} +kP_{3}+...kP_{n} \\=k(P_{1} +P_{2}+P_{3}+...+P_{n})\\=k(1) ....(since k is a constant)\\=k$

Therefore, if k is a constant value, then the expected value of k is E(k)= k.

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