Question

If k is ratio of zeroes of the polynomial 4x2 – 5x – 3, then the value of is plzz annswer fsast

Answer 1

Step-by-step explanation:

This is the answer

Hope u like it

Answer 2

Given : k is ratio of zeroes of the polynomial 4x2 – 5x – 3

To find : Value of k

Solution:

Let say  zeroes  of  4x² – 5x – 3 are  α   & kα

Sum of zeroes  =   α   +  kα  = - (-5/4) = 5/4

=> α (1 + k) = 5/4

Squaring  both sides

=> α² (1 + k)² = 25/16

product of zeroes = α * kα  = - 3/4

=> α²k  =   - 3/4

α² (1 + k)²  / α²k    = (25 /16 ) / ( - 3/4)

=> (1 + k)²  / k    =  - 25 / 12

=> 12(k²  + 2k + 1)   = - 25k

=> 12k² + 24k + 25k + 12 = 0

=> 12k² + 49k +  12 = 0

k = (- 49 ±  √49² -4(12)(12) ) / 24

=> k =  (- 49  ± √1825 )/24

=> k =  (- 49  ± 5√73 )/24

value of k is   (- 49  ± 5√73 )/24

Learn more:

If alpha and 1/alpha are zeroes of polynomial kx²-2x+k²+k . Find ...

https://brainly.in/question/7868632

write the polynomial in variable X whose zero is -k/a​ - Brainly.in

https://brainly.in/question/13634877

. If the zeroes of the cubic polynomial f(x) = kx3 – 8x2 + 5 are alpha ...

https://brainly.in/question/10004198