Question

if k is the average of zeroes of p(x)= 3x³-27x²+10x-9 then show that 1/kis a non terminating decimal​

Answer 1

Step-by-step explanation:

p(x) = 3x³-kx²+5x-7

p(2)=

{3 * 2³ - k * 2² + 5 * 2 - 7 }

= 24 - 4k + 10 - 7=24−4k+10−7

= -4k + 24 + 3

= -4k + 27

now

-4k + 27 = 0

=> -4k = -27

=> k = 27/4

there fore, k is 27/4