if k, (k-2) , 3k are in ap then k=
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Answered by
6
Answer:
Step-by-step explanation:
In AP a2-a1=a3-a2
K-2-k=3k-k+2
-2=2k+2
So,k=0
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Answered by
18
Step-by-step explanation:
SINCE THE NUMBERS ARE IN AP
THEREFORE THEY HAVE THE SAME DIFFERENCE BETWEEN THEM
k-2-k= 3k-k+2
-2=2k+2
-2-2=2k
-4=2k
k= -2
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