Question

IF (k,k/2)is one of the solutions of the equation 3x + 5y = 22. then k =​

Answer 1

Question :-

IF (k,k/2)is one of the solutions of the equation 3x + 5y = 22. then k =

Answer :-

• k = 4

Step by step explanation :-

We have given that,

k and $\rm\frac{k}{2}$ is one of the solutions of the equation 3x + 5y = 22.

We have to find,

♦ Value of k.

$\large\rm \underline{Simple \: method :-}$

We substitute the given solutions in the given equation and we can get easily the value of k.

$\rm:\longmapsto{3(k) + 5 \bigg( \frac{k}{2} \bigg) = 22} \\ \\ \rm:\longmapsto{3k + \frac{5k}{2} = 22 } \: \: \: \: \: \: \: \: \: \: \: \\ \\ \rm:\longmapsto{ \frac{3k(2) + 5k}{2} = 22 } \: \: \: \: \: \: \\ \\\rm:\longmapsto{ \frac{6k + 5k}{2} = 22} \: \: \: \: \: \: \: \: \: \: \: \\ \\ \rm:\longmapsto{11k = 22 \times 2} \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \rm:\longmapsto{k = \cancel\frac{44}{11} } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \rm:\longmapsto{ \boxed{ \rm{k = 4}}} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

The value of k is 4.

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Answer 2

Step-by-step explanation:

Question :-

IF (k,k/2)is one of the solutions of the equation 3x + 5y = 22. then k =

Answer :-

k = 4

Step by step explanation :-

We have given that,

k and \begin{gathered} \rm\frac{k}{2} \\ \end{gathered}2k is one of the solutions of the equation 3x + 5y = 22.

We have to find,

♦ Value of k.

\large\rm \underline{Simple \: method :-}

Simplemethod:−

We substitute the given solutions in the given equation and we can get easily the value of k.

\begin{gathered}\rm:\longmapsto{3(k) + 5 \bigg( \frac{k}{2} \bigg) = 22} \\ \\ \rm:\longmapsto{3k + \frac{5k}{2} = 22 } \: \: \: \: \: \: \: \: \: \: \: \\ \\ \rm:\longmapsto{ \frac{3k(2) + 5k}{2} = 22 } \: \: \: \: \: \: \\ \\\rm:\longmapsto{ \frac{6k + 5k}{2} = 22} \: \: \: \: \: \: \: \: \: \: \: \\ \\ \rm:\longmapsto{11k = 22 \times 2} \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \rm:\longmapsto{k = \cancel\frac{44}{11} } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \rm:\longmapsto{ \boxed{ \rm{k = 4}}} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \end{gathered}:⟼3(k)+5(2k)=22:⟼3k+25k=22:⟼23k(2)+5k=22:⟼26k+5k=22:⟼11k=22×2:⟼k=1144:⟼k=4

The value of k is 4.

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Learn more from brainly :

If x=k^2 and y=k is a solution of the equation 3x-5y-7=0, find the values of k.

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Find the value of k, if x = 2, y = 1 is a solution of the equation 3x -5y –k=0.

https://brainly.in/question/46862578