Math, asked by prajapatipriyanshu94, 7 months ago

If K2 - k. 4k + 3 and 27-k are three consecutive
terms of an AP, find the possible values of k.

Answers

Answered by vedmishra7000

2

Answer:

a2-a1=a3-a2

4k+3(2k+k)=27- k-43-k

2k+k+3=25-5k

3k+3=25-5k

3k+5k=25-3

8k=22

k=11/4

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