Question

If k4 [fe (CN)6] ionized to 10% then the total no. Of particles obtained per mole of this compound is

Answer 1

Answer:

number of particles=1.4

Explanation:

Particles can be ions, atoms or molecules.

$K_4[Fe(CN)_6]$ will dissociates into K+ and 4 [Fe(CN)6]-. So total number of ions will be 5 if $K_4[Fe(CN)_6]$ dissociates completely.

If only 10% ionises then 0.1 of potassium ion will be formed and 0.4 of [Fe(CN)6]- will be formed. So, total number of ions formed will be 0.5.

Since, 10% has dissociated, 0.9 mol of  $K_4[Fe(CN)_6]$ will be undissociated. So, total number of particle will be 1.4.

Answer 2

Answer:

total number of particles in the dissociation is 0.9 + 0.4 + 0.1 = 1.4 moles

Explanation:

We know that when the ionization of K₄[Fe(CN)₆] takes place then the result

is as follows :

K₄[Fe(CN)₆]  -----> 4K⁺ + [Fe(CN)₆]¹⁴⁻

So, we now create the ICE table and it is as follows :

       K₄[Fe(CN)₆]             ----->          4K⁺           +         [Fe(CN)₆]¹⁴⁻

I          1 mole                                   0 mole                    0 mole

C         0.1 mole                               0.4 mole                 0.1 mole(dissociated)

E          0.9 mole                             0.4 mole                 0.1 mole

So, we can see that in equilibrium that the total number of particles in the dissociation is 0.9 + 0.4 + 0.1 = 1.4 moles

ICE TABLE : is a table which represents the initial, change and equilibrium in the form of matrix to bring a simplified form of the calculations for reverse equilibrium reactions.

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