Question

If Ka of a weak acid is 4×10-6 and its concentration is 0.1M.Find pH of solution

Answer 1

$\huge\mathfrak{Answer:-}$

$pH$ $= \frac{1}{2}$$[pK_{a}$$- log c]$

$pH$ $= \frac{1}{2} [ - log4 \times 10^{ - 6} - log10^{ - 1}]$

$pH$ $= \frac{1}{2} [ - 0.6020 + 6 + 1]$

$pH$ $= \frac{1}{2} [7 - 0.602]$

$pH$ $= 3.199$

$\text{Be\:Brainly}$❤️

Answer 2

Hello user

pH = 1/2 (pKa - logC)

pH= 1/2 (-log4 -log10^-6 -log10^-1)

pH= 1/2 (0.6 + 6 + 1)

pH = 1/2 (6.4)

pH = 3.2

Hope it works