If kinetic energy of a body is increased by 300%
then percentage change in momentum will be
(1) 100%
(2) 150%
(3) 265%
(4) 73.2%
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1
Answer:
173.2%
Explanation:
since
KE= mv²/2
KE2/KE1= V2²/V1²= 3
=> V2/V1= √3
momentum= mv
=> mv2/mv1= √3×m
increment = √3
% increment in momentum= √3×100
= 173.2%
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