If kinetic energy of a man 40kg while running is 500J,then his velocity is
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Answered by
1
Answer:
5m/s.
Explanation:
given ,
kinetic energy = 500joule
we know that,
K.E = 1/2 mv^2
so,.
500 = 1/2 *40kg*v^2
1000/40 = v^2
so, velocity will be = 5m/s..
Answered by
4
Solution :-
Given ,
- Kinetic energy ( K.E ) = 500 J
- Mass of man ( m ) = 40 kg
We need to find ,
- Velocity of the man = ?
As we know that ,
K.E = 1/2 m v²
Where ,
- K.E → kinetic energy = 500 J
- m → mass of man = 40 kg
- v → velocity of man = ?
By simplifying the given formula
➸ 2 ( K.E ) = mv²
➸ [ 2 ( K.E ) ]/m = v²
➸ √2(K.E)/m = v
Now , substituting the given values ,
⇒ v = √ 2 ( 500 )/40
⇒ v = √1000/40
⇒ v = √100/4
⇒ v = √10²/√2²
⇒ v = 10/2
⇒ Velocity of man = 5 m/s
Hence , velocity of man = 5 m/s
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