If kinetic energy of a particle is increased by 96% then it's momentum will increase by?
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KE=(P^2)/(2m)
1KE=(96/100)×KE+KE
1P^2=P^2(96/100+1)
1P^2=P^2(196/100)
1P=14%P
Momentum is increased by 14%.
1KE=(96/100)×KE+KE
1P^2=P^2(96/100+1)
1P^2=P^2(196/100)
1P=14%P
Momentum is increased by 14%.
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