Physics, asked by sanika1373, 9 months ago

If kinetic energy of an artificial satellite is 40.09✖10^9J then total energy of that satellite​

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Answered by Anonymous
9

 \underline{ \boxed{ \bold{ \sf{ \huge{ \purple{Answer}}}}}} \\  \\  \star \sf \: Given\\  \\  \mapsto \sf \: kinetic \: energy \: of \: satellite =  40.09 \times  {10}^{9} J\\  \\  \star \sf \: </p><p>To \: Find \\  \\  \mapsto \sf \: total \: energy \: of \: satellite \\  \\  \star \sf \: Formula \\  \\  \mapsto  \underline{\boxed{ \bold{ \sf{ \red{E =  \frac { - KE}{2} }}}}} \\  \\  \star \sf \: calculation \\  \\  \mapsto  \sf \: \bold \: E =  \frac{ - 40.09 \times  {10}^{9} }{2}  =  - 20.045 \times  {10}^{9}  \: J \\  \\  \star \:  \:   \underline{\boxed{ \bold{ \pink{ \sf{E =  -20.045 \times  {10}^{9}  \: J}}}}} \:  \:  \star

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