If Ksp for AgCl is 10‐¹⁰. Calculate solubility of AgCl in 0.1M NaCl solution in mol/litre.
1. 10^-5
2. 10^-9
3. 10^-4
4. 10^-7
Answers
Answered by
0
Explanation:
orrect option is
D
1.6×10
−9
M
AgCl⇌Ag
+
+Cl
−
a 0 0
a-S S S+0.1
k
sp
=1.6×10
−10
=[Ag
+
][Cl
−
]
=S(0.1+S)
k
sp
is value seems to be very small
S value can be ignored, with respect to 0.1 M
1.6×10
−10
=S×0.1
S=1.6×10
−9
M
Hence option B is correct.
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